Curious

Capacitor of P. P. C when a conducting slab placed between it's plates If Co be the initial capacitance of P. P. C                   Co = EoA/d Where, Eo = permittivity of medium between plates  Suppose initially the charges on the capacitor plates are +-Q. Then the uniform electric field set up between the capacitor plates is                    E0 = charge density of plates/Eo Where E0 = electric field between the capacitor plates            W. K. T Charge density of plates = Q/A So, it means                       E0 = Q/AEo  When a conducting slab of thickness t smaller then d is placed between the capacitor plates, free electrons flow inside it so as to reduce the field to zero inside the slab, charges -Q and +Q appera on the upper and lower faces of the slab...

Capacitance of a P. P. C when a dielectric slab placed between its plate Consider P. P. C having two plates of charges +Q and -Q, separation between both plates is d and A be the area of cross section of both plates If Co be the initial capacitance of P. P. C        Co = EoA/d Where, Eo = permitivity of medium between P. P. C                               and  E0 = charge density of plates/Eo  Where, E0 = intial electric field  between P. P. C                 Eo = permitivity  of medium between                           P. P. C W. K. T            Charge density of plates = Q/A   E0 = Q/AEo  If Ep be the E.F inside the slab after introducing it between P. P. C Which is opp...